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AveGali [126]
3 years ago
15

How much times can 8 go into 195

Mathematics
2 answers:
Blababa [14]3 years ago
6 0
Twice.
195÷8=24.375
24.375÷8=3.046875
pashok25 [27]3 years ago
3 0
195 / 8
= 24 (Remainder 3)

So, I guess that the maximun amount of times 8 can go into 195 is 24?
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What is the complement of the supplement of 130 degrees?​
Brut [27]

Answer:

50°

Step-by-step explanation:

180° - 130° = 50°

Mark my answer as the brainliest if this helped! :)

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2 years ago
What set of transformations are applied to parallelogram ABCD to create A'B'C'D'?
denpristay [2]

Answer:

Reflected over the x-axis and rotated 90° counterclockwise

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Extra points!! A candle is 17 in tall after burning for 3 hours. After 5
PIT_PIT [208]

Answer:

1) h=-t+20  

2) 12 inches tall.

Step-by-step explanation:

1) The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

In this case:

y=h (The height of the candle in inches)

x=t (The time in hours)

Then, we can rewrite it:

h=mt+b

Based on the information provided in the exercise, the line passes through these points:

(3,17) and (5,15)

Then, we can find the slope of the line with the formula m=\frac{y_2-y_1}{x_2-x_1}:

 m=\frac{15-17}{5-3}=-1

Now we need to substitute the slope and one of the points into  h=mt+b  and then solve for "b":

17=(-1)(3)+b\\\\b=17+3\\\\b=20

Substituting values, we get that the a linear equation that models the relationship between the heigth of the candle and the time, is:

h=-t+20  

2) We must substitute t=8 into the linear equation  h=-t+20 in order to find the height of the candle after burning 8 hours:

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4 0
4 years ago
Can someone help me with this because I am struggling and if you don't mind show me the steps?
zubka84 [21]

Answer:

C) 1.5 in

Step-by-step explanation:

(7 + 1.5 + 1.5)(5 + 1.5 + 1.5) = 80

4 0
3 years ago
In ΔJKL, the measure of ∠L=90°, JL = 24, LK = 7, and KJ = 25. What is the value of the sine of ∠K to the nearest hundredth?
podryga [215]

<u>Given</u>:

Given that JKL is a right triangle.

The measure of ∠L is 90°

The length of JL = 24, LK = 7, and KJ = 25.

We need to determine the value of sine of ∠K.

<u>Value of sin ∠K:</u>

The value of sin ∠K can be determine using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=K, the side opposite to angle K is JL and the hypotenuse is JK

Thus, we have;

sin \ K=\frac{JL}{JK}

Substituting JL = 24 and JK = 25, we get;

sin \ K=\frac{24}{25}

Simplifying, we get;

sin \ K=0.96

     K=sin^{-1}(0.96)

     K=73.74^{\circ}

Thus, the measure of sine of ∠K is 73.74°

6 0
3 years ago
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