All categories

4 years ago

What is the factored form of 2x^3+ 4x^2- x?

Mathematics

1 answer:

ryzh [129]4 years ago

7 0

Answer:

x (2 x^2 + 4 x - 1)

Step-by-step explanation:

Factor the following:

2 x^3 + 4 x^2 - x

Factor x out of 2 x^3 + 4 x^2 - x:

Answer: x (2 x^2 + 4 x - 1)

You might be interested in

John predicts his football team will score 67 points in the next game. If John's team actually scored 42 points, what was John's

dolphi86 [110]

Answer:

The error percentage was 59.5%

Step-by-step explanation:

John predicts his football team will score 67 points in the next game.

Prediction score = 67

But John's team actually scored 42 points.

Actual scored = 42

We need to find the error percentage of John's using formula.

$\%=\dfrac{\text{|Prediction-exact|}}{exact}\times 100$

$\%=\dfrac{\text{|67-42|}}{42}\times 100$

Percentage error $=\dfrac{25}{42}\times 100$

$=59.52\%$

We need to round off to nearest tenth.

Hence, The percentage error was 59.5%

8 0

3 years ago

Please answer !!!!!!!!!!

anygoal [31]

From top to bottom it goes:
yes
no
no
yes

7 0

2 years ago

Read 2 more answers

A complex number, represented by z = x + iy, may also be visualized as a 2 by 2 matrix

Marat540 [252]

Answer:

Step-by-step explanation:

A) Suppose that we have the complex numbers

$z= x + iy \quad \text{and} \quad \\\\ \tilde{z}=\tilde{x} + i \tilde{y}$

Remember that to sum complex numbers, we sum the real parts of the two numbers to get the real part and the imaginary parts of the two numbers to get the imaginary part. Hence,

$z+\tilde{z} = (x + i y) + (\tilde{x} + i \tilde{y}) = (x + \tilde{x})+i (y+\tilde{y})$

On the other hand, if we sum the matrix visualizations of $z \quad \text{and} \quad \tilde{z}$ we get

$\left[\begin{array}{cc}x &y\\-y&x\end{array}\right] + \left[\begin{array}{cc}\tilde{x}&\tilde{y}\\ -\tilde{y}&\tilde{x}\end{array}\right] = \left[\begin{array}{cc}x + \tilde{x}& y + \tilde{y}\\-(y+\tilde{y})&x+\tilde{x}\end{array}\right]$

which is the matrix visualization of $z + \tilde{z}$ .

To multiply two complex numbers, we use the distributive law to multiplly and then separete the real part from the imaginary part

$z \cdot \tilde{z}= (x + iy) \cdot (\tilde{x} + i \tilde{y})=(x \tilde{x} + i x \tilde{y} + i \tilde{x} y - y\tilde{y} ) = (x\tilde{x}-y\yilde{y})+i(x\tilde{y}+\tilde{x}y)$

Again, if we multiply the matrix visualizations of $z \quad \text{and} \quad \tilde{z}$ we get

$\left[\begin{array}{cc}x&y\\-y&x\end{array}\right]\left[\begin{array}{cc}\tilde{x}&\tilde{y}\\-\tilde{y}&\tilde{x}\end{array}\right] = \left[\begin{array}{cc}x\tilde{x}-y\tilde{y}&x\tilde{y}+y\tilde{x}\\-y\tilde{x}-x\tilde{y}&x\tilde{x}-y\tilde{y}\end{array}\right]$

which is the matrix viasualization of $z\cdot\tilde{z}.$

B) Since the usual matrix operations are consisten with the usual addition and multiplication rules in the complex numbers, we can use them to find the multiplicative inverses of a complex number $z=x+iy$ .

We are looking for the complex number $z^{-1}=(x+iy)^{-1}$ which in terms of matrices is equivalent to find the matrix

$\left[\begin{array}{cc}x&y\\-y & x\end{array}\right]^{-1}= \dfrac{1}{x^{2}+y^{2}} \left[\begin{array}{ccc}x&-y\\y&x\end{array}\right]$

Hence,

$z^{-1}=\dfrac{1}{x^2 +y^2} (x-iy)=\dfrac{1}{|z|^2}(x-iy)$

6 0

3 years ago

Of 1996 people who came into a blood bank to give blood, 294 people had high blood pressure. Estimate the probability that the n

Naddik [55]

We know that out of the 1996 people, 294 had high blood pressure. We can use that to create a fraction.

294/1996 = 147/998 = 0.14729...

The probability of the next person having blood pressure is about 15%.

8 0

3 years ago

Josie deposited $1400 into a traditional IRA that grew to $3700 at her

Bogdan [553]

Answer:

THA ANSWER IS $3701!!!!

Step-by-step explanation:

I JUST DID IT

5 0

3 years ago