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Natasha_Volkova [10]
3 years ago
11

Choose the expressions that DO NOT represent the total area of the big rectangle. Select all that apply.

Mathematics
2 answers:
Flauer [41]3 years ago
5 0

Answer:

i dont know cuz i have 30 resets undertale au rpg and im not smart

Step-by-step explanation:

oee [108]3 years ago
3 0

Answer:

The best answer is: B and C. B: t+5+4. C: 9t

Step-by-step explanation:

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Find the closest point to y in the subspace W spanned by v1 and v
enot [183]

Answer:

The answer is

\bold{  \left[\begin{array}{c}\frac{127}{27} \\ \ &\frac{65}{18} \\ \ &\frac{76}{27}\\ \ &\frac{97}{54}\\\ \end{array}\right]}

Step-by-step explanation:

Given value:

v_1=\left[\begin{array}{c}5&4&3&2\\ \end{array}\right] \\

v_2=\left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] \\    

The value of v_1  \cdot v_2:

= \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]  \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]

The above value "v_1, v_2" are orthogonal vectors that is: v_1 \neq 0, \ \  v_2 \neq 0

\{v_1,v_2\} from the above orthogonal basis of subspace w and the shortest distanc value of vector y:

=\left[\begin{array}{c}3&9&-5&8\\\ \end{array}\right] \\\\

The value of y on W= \frac{y \cdot v_1}{v_1 \cdot v_1} \times v1 + \frac{y \cdot v_2}{v_2 \cdot v_2} \times v_2

= \frac{\left[\begin{array}{c}3&9&-5&8\\\ \end{array}\right] \cdot \left[\begin{array}{c}5&4&3&2\\ \end{array}\right] }{\left[\begin{array}{c}5&4&3&2\\ \end{array}\right] \cdot \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]} \times  \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]  + \frac{\left[\begin{array}{c}3&9&5&-8\\\ \end{array}\right] \cdot \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] }{\left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] \cdot \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]} \times  \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]

= \frac{50}{54} \left[\begin{array}{c}5&4&3&2\\\ \end{array}\right]  - \frac{1}{54}  \left[\begin{array}{c}-4&5&-2&3\\\ \end{array}\right]\\\\

=  \left[\begin{array}{c}\frac{127}{27} \\ \ &\frac{65}{18} \\ \ &\frac{76}{27}\\ \ &\frac{97}{54}\\\ \end{array}\right]

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