Answer:
B.
I hope it will be useful.
Hint:
Since its an isosceles right angled triangle! (Apply the properties)
Or, you can use Pythagoras theorem.
(2x^2=9 v.i.z., on rationalizing 1.5*√2)
Your middle finger and index/pointer.
Answer:
See the explanation.
Step-by-step explanation:
We are given the function f(x) = x² + 2x - 5
Zeros :
If f(x) = 0 i.e. x² + 2x - 5 = 0
The left hand side can not be factorized. Hence, use Sridhar Acharya formula and
and
⇒ x = -3.45 and 1.45
Y- intercept :
Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.
Maximum point :
Not defined
Minimum point:
The equation can be expressed as (x + 1)² = (y + 5)
This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis
Therefore, the minimum point is (-1,-5)
Domain :
x can be any real number
Range:
f(x) ≥ - 6
Interval of increase:
Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.
Therefore, interval of increase is +∞ > x > -1
Interval of decrease:
-∞ < x < -1
End behavior :
So, as x tends to +∞ , then f(x) tends to +∞
And as x tends to -∞, then f(x) tends to +∞. (Answer)
<h2>answer </h2><h2>36</h2>
<h2>i HOPE IT'S HELP </h2>
<h2><u>Graphing</u></h2>
<h3>The graph of this function is shifted 7 units right and shifted 5 units up.</h3>
<h3>f(x) = -2/3(x - 7)² - 5</h3>
<u>Answer:</u>
<u>Explanation:</u>
- Why false? As I noticed, in the equation f(x) = -2/3(x - 7)² - 5, the vertex is (7, -5). The value of a, which is -2/3, is negative. So the graph opens downwards. The graph shifts 7 units to the right, which is correct, but graphing 5 units up is wrong. Why? 5 is negative, so it should be shifted 5 units down.
Wxndy~~