All categories

3 years ago

If your driving 45 miles per hour and your 135 miles away how many hours would it take

Mathematics

2 answers:

storchak [24]3 years ago

8 0

Speed is 45 miles/1 hour.

135 miles x 1 hour/45 miles = 135/45=3 hours

kicyunya [14]3 years ago

4 0

3 hours (im pretty sure)

Hope this helps best of luck i apologize if i am wrong

Have a good day :)

You might be interested in

The difference between a number x and 3 is at least nine Write an inequality for the following sentence.

dybincka [34]

Answer:

3 - x ≥ 9

Step-by-step explanation:

At least in inequality means greater than or equal to (≥)

Difference in mathematics means subtraction

The difference between a number x and 3

3 - x

is at least nine

3 - x ≥ 9

The inequality for the sentence is

3 - x ≥ 9

6 0

4 years ago

A river with large, smooth rocks on the bottom, small and medium sized sediment is moving downstream. Which conditions resulted

zimovet [89]

Answer:

low gradient, high volume

high gradient, low velocity

high gradient, high velocity

Step-by-step explanation:

On E2020

3 0

4 years ago

Read 2 more answers

1. If an equation is true for all values of the variable, then it has?

Alja [10]

Answer:

Infinite solutions

Step-by-step explanation:

Infinite solutions, because every value will work.

7 0

3 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

4 0

3 years ago

Can anyone help me with this math question please I will give brainlist!!

Fiesta28 [93]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers