Answer:
4a + 2b/3
Step-by-step explanation:
focus on 8b/12 first:
factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3
then, go back to 4a:
4a is in its simplest form, it can't be factor
therefore, plus 4a and 2b/3 = 4a + 2b/3
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
The answer is 45 :^))))))))))
