Answer:
The required thickness of the tank wall is 87.7668 mm.
Step-by-step explanation:
Given :
Volume of vessel is V=1.5 m³.
A spherical pressure vessel is of compressed natural gas at P=22 MPa.
If the tank is made of A516 grade 60 steel with a maximum normal stress 150 MPa.
i.e. ![\sigma_{max}=150\ Mpa](https://tex.z-dn.net/?f=%5Csigma_%7Bmax%7D%3D150%5C%20Mpa)
To find : What is the required thickness of the tank wall?
Solution :
The diameter of the vessel is given by,
![\frac{d}{2}=\sqrt{\frac{3V}{4\pi} }](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B2%7D%3D%5Csqrt%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%20%7D)
![\frac{d}{2}=\sqrt{\frac{3\times 1.5}{4\times 3.14}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B2%7D%3D%5Csqrt%7B%5Cfrac%7B3%5Ctimes%201.5%7D%7B4%5Ctimes%203.14%7D%7D)
![\frac{d}{2}=\sqrt{\frac{4.5}{12.56}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B2%7D%3D%5Csqrt%7B%5Cfrac%7B4.5%7D%7B12.56%7D%7D)
![\frac{d}{2}=\sqrt{0.358}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B2%7D%3D%5Csqrt%7B0.358%7D)
![\frac{d}{2}=0.598](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B2%7D%3D0.598)
![d=1.196\ m](https://tex.z-dn.net/?f=d%3D1.196%5C%20m)
Convert into mm,
![d=1.196\times 1000=1196.82\ mm](https://tex.z-dn.net/?f=d%3D1.196%5Ctimes%201000%3D1196.82%5C%20mm)
The thickness of the wall tank is given by,
![t=\frac{Pd}{2\sigma}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BPd%7D%7B2%5Csigma%7D)
![t=\frac{22\times 1196.82}{2\times 150}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B22%5Ctimes%201196.82%7D%7B2%5Ctimes%20150%7D)
![t=\frac{26330.04}{300}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B26330.04%7D%7B300%7D)
![t=87.7668](https://tex.z-dn.net/?f=t%3D87.7668)
Therefore, the required thickness of the tank wall is 87.7668 mm.
Answer:
960.7 ft
Step-by-step explanation:
A right triangle is formed where the distance between Jack and the base of the building is one of the triangles legs and the height of the building plus 5 feet is the other leg (let's call it x). The included angle between the hypotenuse and the distance between Jack and the base of the building is 67°. From definition:
tan(α) = opposite/adjacent
tan(67) = x/400
x = tan(67)*400
x = 965.7 ft
Then, the height of the building is 965.7 ft - 5 ft = 960.7 ft
Answer:
y=4x-8
Step-by-step explanation:
Slope= y1-y2/x1-x2
Slope = 4- (-16)/3-(-2)=4+16/3+2=20/5=4
Equation: y=4x+b
Let y=4 and x=3
4=12+b
b= -12+4
b=-8
Therefore: y=4x-8
Answer: No you don't have enough
Step-by-step explanation:
69.99 Before tax
8.5% tax
Unrounded tax: 5.9491499999999995
Tax: $5.95
Total: $75.94
You don't have enough
1.
D. Vertical angles
2.
B. RT is an angle bisector of angle QRS