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Debora [2.8K]
3 years ago
12

Initial Knowledge Check

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

0

5

3

becos i know UwU

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Alyssa needs 7 5/8 inches of ribbon for one project and
WITCHER [35]

Answer:You are correct but you do not need to round it, the inches of ribbon is short by 0.75 inches. Hope this helps you, have great day!

Step-by-step explanation:

6 0
3 years ago
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Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant
ludmilkaskok [199]
The complete question in the attached figure

we have that
tan a=7/24    a----> III quadrant
cos b=-12/13   b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

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Timmy went running and used 500 calories. What would Timmy have to do to get those
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Answer:

Eat a food with 500 calories

Step-by-step explanation:

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PLEASE I NEED HELP
Brums [2.3K]

Answer:

9

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Need help ASAP. Choose the expression that represents a cubic expression.
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The third option

4×3 - 3×2 -2x + 11

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