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Lerok [7]
3 years ago
13

La temperatura mínima en una ciudad el día lunes fue de –2 ºC y la máxima fue de 7 ºC. ¿Cuál fue la variación de temperatura en

el día?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

La variación de temperatura en el día es 9°C.

Step-by-step explanation:

Cuando tenemos dos valores, uno máximo M y uno mínimo m, la variación entre esos valores es la diferencia (la resta) entre el valor máximo M y el valor mínimo m

variación = M - m

En este caso sabemos que la temperatura mínima es -2°C

La temperatura máxima es 7°C

La variación sera entonces:

Variación = 7°C - (-2°C)

Recordar la regla de los signos:

(-)*(-) = (+)

Entonces:

Variación = 7°C - (-2°C) = 7°C + 2°C = 9°C

La variación de temperatura en el día es 9°C.

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Can someone please help me
PtichkaEL [24]

Answer:

The size is 37.5 degrees

Step-by-step explanation:

The total angle in the triangle is 180

Since the other two angles are congruent. it means that they are equal

Let us call each of the angles x

Mathematically,

x + x + 105 = 180

2x = 180-105

2x = 75

x = 75/2

x = 37.5

7 0
3 years ago
One fabric cost $15.00 for 2 yards. Another cost $37.50 for 5 yards. Do both yards cost the same? Explain.
omeli [17]

Answer:

Yes.

Step-by-step explanation:

Both yards do cost the same.

$15.00 divided by 2 is equal to 7.5.

$37.50 divided by 5 is equal to 7.5.

Therefore, both yards cost the same.

3 0
3 years ago
Find the interval(s) of upward concavity on this accumulation function.
maxonik [38]

\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))

Hope this helps.

6 0
3 years ago
There are 75 people in a room. Of these people, 2/5 are from Germany. If 4/9 of the people who are not from Germany are from Fra
Alex Ar [27]

Answer:

25 people are not from Germany or France.

Step-by-step explanation:

1. You first want find out what is the number of people from Germany.

So you would find...

2/5 of 75

or

2/5*75= 30 people from Germany

2. Next you want to to find out the number of people from France.

So you would do the following...

75-30=45 (Subtract the number of people from Germany from 75 so you can get the total number of people from France and other countries)

4/9 of 45 to find the number of people from France.

4/9 *45= 20

3. Lastly you need to find the people who are from neither of the countries listed above.

Add 30+20= 50

Then subtract that number from 75.

75-50= 25 people who are from neither France or Germany.

Voila! This is your answer. Hope this helps! :)

7 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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