3 years ago

Find all solutions to each quadratic equation

1 answer:

6 0

I hope this helps you

2x^2-4x+7=0 a=2 b=-4 c= 7

disctirminant =b^2-4ac

disctirminant =(-4)^2-4.2.7

disctirminant = 16-56= -40

x=-b+square root of disctirminant ÷2a

x=4+2square root of (-10)/4

x=2+square root of (-10)/2

x'=4 -2 square root of (-10)/4

x'=2 -square root of (-10)/2

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what is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point) y − 5

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According to the question, the line is through the points $(0,5)$ and $(-2,11)$

To calculate the slope using standard formula that is :

$m = \frac{(y(2)-y(1))}{(x(2)-x(1))} = \frac{(11-5)}{(-2-0)} =\frac{6}{-2} = -3$

Now the slope equation will be: $m(x(2)-x(1)) = (y(2)-y(1))$

$y-5 =(-3)(x-0) = y = -3(x)+5$

The slope-intercept form is: $y = -3x+5$

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

brainly.com/question/14037984

#SPJ4

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