Answer:
We have 6 flamy and 10 Elephants
Step-by-step explanation:
A local zoo has flamingos and elephants in one exhibit.
Flamingos have 2 legs
Elephants have 4 legs
Let the number of
Flamingos = x
Elephants = y
There are 16 animals in the exhibit
= x + y = 16..... Equation 1
x = 16 - y
The animals have a risk of 52 legs.
2 × x + 4 × y = 52
2x + 4y = 52..... Equation 2
We substitute 16 - y for x in Equation 2
2(16 - y) + 4y = 52
32 - 2y + 4y = 52
- 2y + 4y = 52 - 32
2y = 20
y = 20/2
y = 10
Solving for x
x = 16 - y
x = 16 - 10
x = 6
Hence, we have
Flamingos = x = 6 flamingos
Elephants = y = 10 Elephants
