Solve the following question using the elimination method :)

5. If necessary,<br> the hundredths.<br> .04 + 1.8 =<br> round to

s2008m [1.1K]

Answer:1.84

Step-by-step explanation: We can add this in a very easy way.

Step 1- We can put the 1 in the ones place as if there is no number before a decimal (which is the case for the first number) we can assume it is 0.

Step 2- We can then place the decimal point after the 1 and then put 0.8 since there are no more numbers that are at the tenths

Step 3- At the end we add the .04 (also known as 0.04) as there are no more places in both the numbers that are in the hundredths (and in 1.8, it can also be known as 1.80 as there are none!)

Hope this helps!

I would appreciate if you can mark me brainliest :)

4 0

2 years ago

The sum of two numbers is 35 . The smaller number is 17 less than the larger number. What is the largest and the smallest number

Aleks [24]

X + x - 17 = 35
2x - 17 = 35
+ 17
2x = 52
÷ 2
x = 26 (larger number)

35 - 26 = 9 (smaller number)

6 0

3 years ago

Read 2 more answers

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co

Ira Lisetskai [31]

Answer:

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

$df = 103-1 = 102$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have $T = 2.63$ .

Now, we need to find the standard deviation of the sample. That is:

$s = \frac{0.56}{\sqrt{103}} = 0.055$

Now, we multiply T and s

$M = T*s = 2.63*0.055 = 0.145$

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0

4 years ago

Assume that the pond contains 90 fish: 64 purple, 25 green, and 1 red. A contestant pays $0.55 to randomly catch one fish and re

Licemer1 [7]

Answer:

The carnival is losing (on average) $0.15 on each play

Step-by-step explanation:

To find out how much the carnival wins or looses in each play one subtract the expected value (EV) from each play from the amount charged by the carnival for each play ($0.55). If the expected value is higher than what the carnival charges, the carnival is losing money.

Expected is the sum of the payouts of each bet multiplied by its likelihood:

$EV= \frac{64*0.40+25*1.15+1*9.00}{90}\\EV= 0.70$

Since the expected value is higher than $0.55, the carnival is losing money, on average, on each play:

$0.55-0.7 = -0.15$

The carnival is losing (on average) $0.15 on each play

6 0

3 years ago

The point (-3, 6) is on a line with a slope of 4.

postnew [5]

Answer:

51

Step-by-step explanation:

The caty

7 0

3 years ago