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saveliy_v [14]
3 years ago
12

HELP! WILL GIVE BRAINLY

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer: 44

Step-by-step explanation:

Harper is 17 and Cadence is 44.

Step-by-step explanation:

First, we can set up an equation to displays the sum of both ages.

Let x = Harper's age and y = Cadence's age

x+y=61

8 years ago, this means the sum will decrease by a total of 16 as we have to subtract 8 from both variables

The equation to represent 8 years ago is: x+y=45

Now we can write another equation to represent Cadence being 4 times older than Harper (8 years ago)

y=4x

We can substitute this back into the equation we had for the ages 8 years ago.

x+(4x) = 45

5x=45

x=9

Now, Harper's age 8 years ago is 9 years old. We add 8 to this number to determine that Harper is currently 17 years old.

We can insert this into the original equation to determine Cadence's age.

17+y=61

y=44

Thus, Cadence is currently 44 years old

wariber [46]3 years ago
3 0

Answer:

Harper is 17 and Cadence is 44.

Step-by-step explanation:

First, we can set up an equation to displays the sum of both ages.

Let x = Harper's age and y = Cadence's age

x+y=61

8 years ago, this means the sum will decrease by a total of 16 as we have to subtract 8 from both variables

The equation to represent 8 years ago is: x+y=45

Now we can write another equation to represent Cadence being 4 times older than Harper (8 years ago)

y=4x

We can substitute this back into the equation we had for the ages 8 years ago.

x+(4x) = 45

5x=45

x=9

Now, Harper's age 8 years ago is 9 years old. We add 8 to this number to determine that Harper is currently 17 years old.

We can insert this into the original equation to determine Cadence's age.

17+y=61

y=44

Thus, Cadence is currently 44 years old

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