The total number of 3 digit even numbers is 450
Step-by-step explanation:
Step 1 :
We need to determine the number of 3 digit numbers which is even and the leftmost digit is not zero .
The 3 digits with left most digit not equal to zero starts from 100 and goes up to 998
If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.
Step 2:
The last number l in this series is 998 .
So we have
a = 100
l = 998
d = 2
The nth term in the arithmetic progression is given by a + (n-1) d
so substituting the above values we get
100 + (n-1) 2 = 998
2n = 900 => n = 450
Step 3 :
Answer :
The total number of 3 digit even numbers is 450
divide the two:
52.50 / 7 = 7.50 per hour
Slimination
multiply first equaiton by 2
2x+6y=10
add to second equiaotn
2x-2x+6y-6y=10-10
0=0
this is true so therfor they are the same equaiton
so solve
x+3y=5
3y=-x+5
y=-1/3x+5/3
subsituter values for x and get valuse for y
if x=2 then y=1
I think the The answer 1/1 or1/2! If it is not correct then ask some one else
Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
i.e. 
i.e.
i.e. i.e. 
Hence, the probability of 4 wins in the next 5 games is 0.128.
