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3 years ago

9

Steve has 8 biscuits in a tin. There are 5 digestive and 3 chocolate biscuits. Steve takes two biscuits at random from the tin.

Work out the probability that he chooses two different types of biscuits.

2 answers:

Talja [164]3 years ago

8 0

Answer:

15/28

Step-by-step explanation:

Fudgin [204]3 years ago

5 0

Answer:

5/7

Step-by-step explanation:

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Pls answer pls ok ok ok ok o ok

cestrela7 [59]

Answer: a

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Flora's Florist charges a standard delivery charge of

goldenfox [79]

Answer: $10.00 + 4.50r

r = rose

$10.00 = delivery charge

$4.50 = charge per rose

7 0

2 years ago

Help me please ^^ much appreciated

Reil [10]

Answer:

C

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{16}{28}$ , thus

∠ C = $sin^{-1}$ ( $\frac{16}{28}$ ) ≈ 34.85° ( to 2 dec. places )

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20

Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

$\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx$

Let $f(x) = \sqrt{1 + x^3}$ . Compute the inverse:

$f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}$

and we immediately notice that $f^{-1}(x+1)=\sqrt[3]{x^2+2x}$ .

So, we can write the given integral as

$\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx$

Splitting up terms and replacing $x \to x-1$ in the first integral, we get

$\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}$

7 0

2 years ago

Nonamiya [84]

Answer:

I belive it would be 1/5. ;;;

4 0

3 years ago