The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
where is the function? where are the equations?
Domain are x values (independent variable);
Speed would be independent so what speeds can be used ? -30 mph, 30 mph, 1000 mph?
Can a car go 0 mph?
What is realistic?
I would say 0 greater or equal to x greater than whatever you think is beyond the max that a car can go.
Answer:
6, -7
Step-by-step explanation:
when I followed those instructions, that's what i got.
:)
Answer:
$27.5
Step-by-step explanation:
Other solution
38.2 X 0.8 = 30.56 (20% off)
30.56 X 0.9 = 27.504 (Another 10% off)