If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
I found the image that accompanied this problem.
We need to solve for the area of the sector.
A = n/360 * π * r²
A = 85/360 * 3.14 * 5²
A = 0.2361 * 3.14 * 25
A = 18.5347
Answer is C. 18.5 square meters.
The answer to this would be 480. ((:
Parallel because congruency and parallelism is somehow similar and that word fits in perfectly
The school year would be 1981-1982
