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Roman55 [17]
3 years ago
13

A tin man has a head that is a cylinder with a cone on top. The height of the cylinder is 12 inches and the slant height of the

cone is 6 inches. The radius of both the cylinder and the cone is 4 inches. What is the surface area of the tin man's head in terms of pi?
A) 136π in²
B) 152π in²
C) 168π in²
D) 172π in²

I already figured out the surface area of the cylinder (128π in).. I just don't know how to include the cone into the equation. I'm stumped.. Please help
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0
The answer would be C
barxatty [35]3 years ago
6 0

Answer:

136\pi in^2

Step-by-step explanation:

Height of cylinder = 12 inches

Radius of cylinder = 4 inches

Since we are given that A tin man has a head that is a cylinder with a cone on top.

So, Surface area of cylinder = Curved surface area of cylinder + Area of one base

                                              =2 \pi r h +\pi r^2

                                              =2 \pi (4)(12)+\pi(4)^2

                                              =96 \pi +16\pi

                                              =112\pi

Cone is joined on the top of the cylinder

So, we are required to find the lateral surface area of cone .

Slant height of cone = 6 inches

Radius of cone = 4 inches

So, Lateral surface area of cone = \pi r l

                                                      = \pi (4) (6)

                                                      = 24\pi

Thus the total surface area = 112\pi + 24\pi

                                              = 136\pi in^2

Hence the surface area of the tin man's head in terms of pi is 136\pi in^2

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stich3 [128]
What’s your question ?
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2 years ago
Values for the area A of the rectangle shown are 12 ≤ A ≤ 36.
Step2247 [10]

A compound inequality is used to combined multiple inequalities.

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We have:

12 \le A \le 36

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The area of the rectangle is:

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So, we have:

A =2x \times 3

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Divide through by 6

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Hence,

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Read more about compound inequalities at:

brainly.com/question/17957246

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Hey there! :)

Answer:

\huge\boxed{n = 25}

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