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2 years ago

You earn $28 for washing 4 cars. How much do you earn for washing 3 cars?

Mathematics

2 answers:

a_sh-v [17]2 years ago

8 0

Answer:

21 dollars

Step-by-step explanation:

vfiekz [6]2 years ago

8 0

Answer:

$21

Step-by-step explanation:

Make the original statement into a ratio.

$28/4

Simplify the fraction above.

$28/4 = 7

So, you earn $7 per car you wash.

As a result, you multiply $7 by the number of cars the question is asking you for. In this case it is 3 cars.

So, you multiply 7 x 3

7 x 3 = 21

Therefore, you will earn $21 for washing 3 cars.

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PLEASE HELP!!! HELP ME ANSWER A

olga nikolaevna [1]

Answer:

125,000 * 1.0625^t years

Step-by-step explanation:

compound interest = increase in amount

100 + 6.25 = 106.25

106.25/100 = 1.0625

therefore, 125,000 * 1.0625^years

6 0

2 years ago

~~~~~~~~~~~`````````````````

bixtya [17]

Answer:

Step-by-step explanation:

(-3/4)x + 9 = (-1/2)x + 8

9 - 8 = (-1/2)x + (3/4)x

1 = (1/4)x

x = 4

y = (-3/4)4 + 9

y = -3 + 9

y = 6

3 0

2 years ago

if your teacher tells you to do questions 28 through 41 in your math book for homework, how many questions is that

katrin2010 [14]

Its 14.
30-40 is 11, 28-29 is 2, and 41 is 1.

5 0

3 years ago

Please help me with this question.

Stels [109]

Step-by-step explanation:

Mean of the origibal set = 20

No. of terms = 10

Sum = Mean x No. of terms

= 20 x 10 = 200

The sum of additional numbers to make the new set of observstion is 4 + 8 + 12...... + 40 = 220

New Sum = 200 + 220 = 420

The no of terms stay the same

New Mean = New Sum/ N

= 420/10

= 42

7 0

2 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

2 years ago