For this case, the first thing we must do is identify the linear expressions.
first linear expression = y1 = x
second linear expression = y2 = 5
We have then that the difference of the second with respect to the first is:
y2-y1 = 5-x
Answer:
The difference when the second line is here is subtracted from the first is:
5-x
Answer:
104
Step-by-step explanation:
tan(60) = opposite/adjacent
tan(60) = X/60
X = 60×tan(60)
X = 103.9230484541
X = 104 (3 sf)
2:3:4 gives 9 equal parts.
1.20 divided by 9 is 0.133.
2 * 0.133 would be 0.266m
3 * 0.133 would be 0.399m
4 * 0.133 would be 0.533m
To check this calculate 0.533 + 0.399 + 0.266 would be 1.198m (close enough)
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
<span>r means radius so it can't be negative.
<=>
A = 4 pi r²
r = sqr (A / 4pi)
</span>
