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diamong [38]
3 years ago
10

A scientist is measuring the temperature change in a medical compound the temperature dropped 11 Fahrenheit per hour from the or

iginal temperature after four hours of temperature was 90 in Fahrenheit find the compounds original temperature
Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer: the original temperature is

123 °Fahrenheit

Step-by-step explanation:

The temperature dropped 11 Fahrenheit per hour from the original temperature. This means that the rate at which it is dropping is in arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term(original temperature) of the sequence.

d represents the common difference.

n represents the number of terms(hours) in the sequence.

From the information given,

d = - 11 degrees (it is decreasing)

When n = 4 hours, T4 = 90

We want to determine the value of the first term, a. Therefore,

T4 = 90 = a - 11(4 - 1)

90 = a - 11 × 3

90 = a - 33

a = 90 + 33

a = 123 °Fahrenheit

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Answer:

3.8ft

Step-by-step explanation:

Given data

The total length of the rope= 9ft

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6 0
3 years ago
Perform the indicated operations below and simplify ((a+b)/4) + ((2a-b)/5).
ArbitrLikvidat [17]

Answer:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{13a}{20} +\frac{b}{20}

Step-by-step explanation:

We have:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}

We can use <em>common denominator</em>.

Observation:

If you have, \frac{a}{b} +\frac{c}{d}=\frac{(a*d)+(c*b)}{b*d}

Then,

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{5(a+b)+4(2a-b)}{4*5}

Using <em>distributive property</em>:

Observation:

c(a+b)=ca+cb

\frac{5(a+b)+4(2a-b)}{4*5}=\frac{5a+5b+8a-4b}{20}=\frac{(5a+8a)+(5b-4b)}{20}

Finally,

\frac{(5a+8a)+(5b-4b)}{20} =\frac{13a+b}{20}=\frac{13a}{20} +\frac{b}{20}

The answer then is:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{13a}{20} +\frac{b}{20}

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