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2 years ago

SSA triangles always have two solutions. (A.) True (B). False

Mathematics

2 answers:

scoray [572]2 years ago

8 0

Answer:

No, Ssa triangle always not have two solutions

Step-by-step explanation:

the solution can be one, two or there will be no dolution. So this statement is false.

Marina86 [1]2 years ago

5 0

The answer is false. hopefully i helped

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2 years ago

Find the measure of the angle indicated in bold

11Alexandr11 [23.1K]

The answer is 50.

i came to this conclusion when using this equation: 15x+5=2+16x
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3 years ago

P³ = 1/8 please help me if anybody can .

ivanzaharov [21]

Answer:

$p= \dfrac{1}{2}$

Step-by-step explanation:

Given equation:

$p^3=\dfrac{1}{8}$

Cube root both sides:

$\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}$

$\implies p= \sqrt[3]{\dfrac{1}{8}}$

$\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:$

$\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}$

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$\implies p= \dfrac{1}{8^{\frac{1}{3}}}$

Rewrite 8 as 2³:

$\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}$

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