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Shkiper50 [21]
3 years ago
10

Which is unnecessary to include when accurately drawing ray diagrams?

Physics
2 answers:
Gwar [14]3 years ago
8 0

Answer:

focal length

Explanation:

VashaNatasha [74]3 years ago
6 0

Answer:

Focal length

Explanation: No need for one...

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I don't know the answer to that
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The total energy in a substance as a result of the motion and position of all the particles is _________. a. heat b. temperature
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The answer would be Thermal Energy.
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3 years ago
The volume of water in the Pacific Ocean is about 7.00 × 108 km3. The density of seawater is about 1030 kg/m3. For the sake of t
oee [108]

The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.

By definition the gravitational potential energy is given by,

PE=\frac{GMm}{r}

Where,

m = Mass of Moon

G = Gravitational Universal Constant

M = Mass of Ocean

r = Radius

First we calculate the mass through the ratio given by density.

m = \rho V

m = (1030Kg/m^3)(7*10^8m^3)

m = 7.210*10^{11}Kg

PART A) Gravitational potential energy of the Moon–Pacific Ocean system when the Pacific is facing away from the Moon

Now we define the radius at the most distant point

r_1 = 3.84*10^8 + 6.4*10^6 = 3.904*10^8m

Then the potential energy at this point would be,

PE_1 = \frac{GMm}{r_1}

PE_1 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.904*10^8}

PE_1 = 9.05*10^{15}J

PART B) when Earth has rotated so that the Pacific Ocean faces toward the Moon.

At the nearest point we perform the same as the previous process, we calculate the radius

r_2 = 3.84*10^8-6.4*10^6 - 3.776*10^8m

The we calculate the Potential gravitational energy,

PE_2 = \frac{GMm}{r_2}

PE_2 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.776*10^8}

PE_2 = 9.361*10^{15}J

7 0
3 years ago
Why are the surface features of the moon essentially unaltered since youth
zmey [24]

Because there is no wind, rain, snow, sleet, or people to wear them down,
and no rivers, streams, or floods to cover them over.

8 0
3 years ago
Calculate the induced electric field in a 54-turn coil with a diameter of 19.5 cm that is placed in a spatially uniform magnetic
storchak [24]

Answer:

E = 3.049 N/C

Explanation:

Induced electric field = e/2 *(pi) *r

Induced electric field = e /(3.14 *19.5)  - Eq (1)

e = (pi)r^2*B/t

= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1

= 1.867 V

Substituting this value in equation 1, we get –  

E = 1.867 V/(3.14 *19.5/100)  

E = 3.049 N/C

4 0
3 years ago
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