Question

Calculate the induced electric field in a 54-turn coil with a diameter of 19.5 cm that is placed in a spatially uniform magnetic field of magnitude 0.5 T so that the face of the coil and the magnetic field are perpendicular. This magnetic field is reduced to zero in 0.1 seconds. Assume that the magnetic field is cylindrically symmetric with respect to the central axis of the coil.

Answer 1

Answer:

E = 3.049 N/C

Explanation:

Induced electric field = e/2 *(pi) *r

Induced electric field = e /(3.14 *19.5)  - Eq (1)

e = (pi)r^2*B/t

= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1

= 1.867 V

Substituting this value in equation 1, we get –  

E = 1.867 V/(3.14 *19.5/100)  

E = 3.049 N/C