Answer:
<u>path</u>
Explanation:
The sub-folders and folders set that MATLAB searches through in order to locate M-file or a command is known as the path.
These files are stored in the user path which is stored in the user path directory in it.
We usually run the function , i.e., user path function in order to know the location of the folder stored or command or the M-file.
A callout is a type of text box that also includes a line for pointing to any location on the document. A callout appears under the SHAPES <span>menu of the word processing program. The answer that completes this statement is the word "shapes". Hope this answers your question. </span>
Answer:
b) one needs to follow through all phases, assessment, design, deploy and manage security
Explanation:
The security life cycle is a process in which it involves the security artifacts for developing the software through a lifecycle. It contains a detailed plan that derives how to create an application form
At the time when the requirements and activity related to design is finished the next step is the software implementation. In this, the developers begins with the coding as per the requirements and designs discussed in the last step
Therefore according to the given options, the second option is correct
Answer:
All of Given
Explanation:
JSP provides a number of implicit objects which are made available by the container and can be used directly in scriptlets. These objects include:
- session
- application
- config
- out
- request
- response
- pageContext
- page
- exception
Example usage:
<% session.setAttribute("userid","demoid"); %>
<% application.getContextPath(); %>
<% out.println(config.getServletName()); %>
Answer:
In C:
#include <stdio.h>
#include <math.h>
int main(){
float f0,r,temp;
r = pow(2.0,1.0/12);
printf("f0: "); scanf("%f", &f0);
temp = f0;
for(int i = 0; i<=4;i++){
f0 = f0 * pow(r,i);
printf("%.2lf ", f0);
f0 = temp; }
return 0;
}
Explanation:
This declares f0, r and temp as float
float f0,r,temp;
This initializes r to 2^(1/12)
r = pow(2.0,1.0/12);
This prompts the user for f0
printf("f0: "); scanf("%f", &f0);
This saves f0 in temp
temp = f0;
This iterates the number of keys from 0 to 4
for(int i = 0; i<=4;i++){
This calculates each key
f0 = f0 * pow(r,i);
This prints the key
printf("%.2lf ", f0);
This gets the initial value of f0
f0 = temp; }
return 0;
