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2 years ago

Which value is a solution to the inequality x < 4?

1 answer:

3 0

The answer is x > 4.5.

Explanation:

-24 > -6(x - 0.5)

-24 > -6x + 3

6x > 3 + 24

6x > 27

x > 27/6

x > 4.5

Hope this helps :)

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Jo rode her bicycle 8 miles on Tuesday and 10 miles on Wednesday. What is the mean number of miles she rode her bike in the two

Contact [7]

Mean equals average

So 8 plus 10 equals 18

18 divided by 2 is 9

Mean is 9

6 0

3 years ago

Brainliest!!!!!!

Nataly [62]

Answer:

2x² - 12x + 13

Step-by-step explanation:

Given following:

k(x) = 2x² - 5

p(x) = x - 3

Start solving from right to left across the function.

Steps:

k[p(x)]

k[x - 3]

2(x - 3)² - 5

2(x² - 6x + 9) - 5

2x² - 12x + 18 - 5

2x² - 12x + 13

4 0

1 year ago

Read 2 more answers

16) (1 Point) : Solve the equation

Marat540 [252]

Answer:

(B)

4 +/- 3 sqrt(2) or 4+3sqrt(2) and 4-3sqrt(2)

Step-by-step explanation:

4(c-4)^2=72

4(c-4)(c-4)=72

foil the parenthesis (first, outside, inside, last)

4(c^2 -4c -4c +16)=72

4(c^2-8c+16)=72

divide each side by 4

c^2-8c+16=18

subtract 18 from both sides

c^2-8c-2

use quadratic formula

((-b +/- sqrt((-b^2)-4ac)))/2a

((-(-8)+/-sqrt((-8)^2-4(1)(-2)))/2(1))

(8+/-sqrt(64-(-8)))/2

(8+/-sqrt(64+8))/2

(8+/-sqrt(72))/2

(8+/-sqrt(36 * 2))/2

(8+/-6sqrt(2))/2

4+/-3sqrt(2)

or 4+3sqrt(2) and 4-3sqrt(2)

3 0

2 years ago

Help plz if your good at finding the area of the compound figure plz help if you don’t know the answer your not needed but if yo

spin [16.1K]

Answer:

96cm^2

Step-by-step explanation:

We can divide it into two rectangles: 7x8 and 10x(12-8), arriving at the solution of 7cm*8cm + 10cm*4cm = 56cm^2 + 40cm^2 = 96cm^2

We can also divide it into two rectangles: 12x7 + (12-8)x(10-7), arriving at 12cm*7cm + 4cm*3cm = 84cm^2 + 12cm^2 = 96cm^2

We could also divide it to one big rectangle and one "negative" rectangle of 10x12 and -8x(10-7), arriving at 10cm*12cm - 8cm*3cm = 120cm^2 - 24cm^2 = 96cm^2

6 0

3 years ago

A test is used to assess readiness for college. In a recent year, the mean test score was 20.3 and the standard deviation was 4

Vlada [557]

Answer:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.

For this case we have the mean and the deviation given:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

6 0

3 years ago