Sec 5A = cosec 7A, prove that A = 7.5°
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See the attached figure
we know that
[<span>the area of the trapezoid]=[area rectangle]+2*[area triangle]
</span>[the area of the trapezoid]=[14*12]+2*[12*2/2]=192 in²
the answer is 192 in²
we know that
[<span>the area of the trapezoid]=[area rectangle]+2*[area triangle]
</span>[the area of the trapezoid]=[14*12]+2*[12*2/2]=192 in²
the answer is 192 in²