Question

Solve the equation. Check the solution.

Answer 1

The value of x is $\frac{-11}{3}$.

Solution:

Given equation:

$\frac{-2}{x+4}=\frac{4}{x+3}$

To find the value of x:

$\frac{-2}{x+4}=\frac{4}{x+3}$

Do cross multiplication.

$-2(x+3)=4(x+4)$

–2x – 6 = 4x + 16

Add 6 on both sides of the equation.

–2x = 4x + 22

Subtract 4x on both sides of the equation.

–6x = 22

Divide by –6 on both sides of the equation.

$x=\frac{-22}{6}$

$x=\frac{-11}{3}$

Checking:

Substitute x value in left side term.

$\frac{-2}{x+4}=\frac{-2}{\frac{-11}{3}+4 }$

        $=\frac{-2}{\frac{-11+12}{3}}$

        $=\frac{-2}{\frac{1}{3}}$

        = – 6

Substitute x value in right side term.

$\frac{4}{x+3}=\frac{4}{\frac{-11}{3}+3 }$

         $=\frac{4}{\frac{-11+9}{3}}$

         $=\frac{4}{\frac{-2}{3}}$

         = – 6

Hence the value of x is $\frac{-11}{3}$.