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andrew11 [14]
3 years ago
13

O 14,000 16) How many zeros will be in the product of 4 x 500?*​

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

3 zeros

Step-by-step explanation:

4*500=2000

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6. Five years ago, Ross was N times as old as
Tema [17]

Answer:

14N+5

Step-by-step explanation:

Five years ago; Rose Nx

Amanda x

Now; Rose Nx+5

Amanda x+5=19

x=19-5=14years

Rose(NOW) =14N+5

8 0
2 years ago
6. Write the factors of 36. Separate the factors with commas. ​
faltersainse [42]
1,2,3,4,6,12,18,36 are the factors!
8 0
3 years ago
Parallel lines s and t are cut by a transversal, r, as shown
Natalija [7]

Answer:

18

Step-by-step explanation:

i just took the test and got a 100% :)

8 0
3 years ago
Read 2 more answers
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
A radio telescope has a parabolic surface, as shown below.
krek1111 [17]
OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0

Because the roots of the equation are 0 and 12, we know the formula is therefore of the form

y = ax(x - 12), for some a

So put in x = 6

-9 = 6a(-6)

9 = 36a

a = 1/4

So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x

The gradient of this is dy/dx = 0.5x - 3

The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8

Gradient of the parabolic mirror at x = 4 is -1

So the gradient of the normal to the mirror at x = 4 is therefore 1.

Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.

So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
5 0
2 years ago
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