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klasskru [66]
3 years ago
14

Solve the polynomial equation = 3

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

lol the is no equation there to solve

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PLEASE ANSWER- Which sequence is graphed below?
boyakko [2]

Answer:

pretty sure its C, good luck

6 0
3 years ago
Travis owns a stock in the SBO Company. after the first year of ownership the stock is worth $45 per share. travis estimates tha
Roman55 [17]
<span>1st year value =45$ 2nd year value=45+2.80$=47.80$ 3rd year value=47.8+2.80$=50.60$ 4th year value=50.60+2.80=53.40$ 5th year value=53.40+2.80=56.20$ ater 5 years value of share becomes 56.20$ or share after 5 years= 45+4*2.80=45+11.20=56.20$</span>
5 0
3 years ago
Solve the following system of equations using elimination (Do not multipy)
aivan3 [116]
1) 5x - 6y = -32 --> equation 1
    3x + 6y = 48  --> equation 2
eliminating y from both of the equations and adding the rest of the terms
we get,
    8x = 16
    dividing 8 on both sides
    x = 2
Substituting the value of x in equation 1
   5(2) - 6y = -32
    10 - 6y = -32
   -6y = -12 ( dividing both sides by -6)
    y = 2

2) 
-3x - 3y = 9 ---> equation 1
      3x - 4y = 5 --> equation 2
eliminating x from both equations and adding the rest of the terms
 we get,
     -7y = 14 ( dividing both sides by -7 )
      y = -2
Substituting the value of y in the equation 1
    -3x - 3(-2) =9
    -3x + 6 = 9 (subtracting both sides by -6)
     -3x = 3
     x = -1

Hope this helps you..  :)
5 0
3 years ago
Read 2 more answers
Multiply and solve for x: x(x + 12) – 8x = 14 + x(x – 4)
erik [133]
Using the distribution method:

x^2 + 12x - 8x = 14 + x^2 - 4x

x^2 + 4x = x^2 - 4x + 14

Now, I'm isolating x by moving all the x's onto one side of the equation:

x^2 - x^2 + 4x + 4x = 14

Combine like terms (x^2 cancels out):

8x = 14

x = 14/8

Simplified: x = 7/4
6 0
3 years ago
What is the area of the parallegram?<br> -104m<br> -88m<br> -56<br> -32
Bumek [7]

Area is Length X width.

Length = 4+7 = 11 m

Width = 8 m

Area = 11 x 8 = 88 m^2

5 0
3 years ago
Read 2 more answers
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