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3 years ago

The sum of 3 consecutive odd numbers is 183 ?

Mathematics

2 answers:

irina [24]3 years ago

6 0

Answer:

The answer is 61.

Step-by-step explanation:

Let, the numbers are: x, (x+2), (x+4)

Now, x+x+2+x+4 = 183

3x + 6 = 183

3x = 177

x = 59

So, second number would be: (x+2) = (59+2) = 61

horrorfan [7]3 years ago

3 0

Answer:

Step-by-step explanation:

n+(n+2)+(n+4)=183

3n+6=183

3n=177

n=59

So the three numbers are 59, 61, and 63.

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Jones Street is parallel to Lincoln Street, and both streets are intersected by Elm Street and Avenue A. Jones Street J 105° m E

kvv77 [185]

We have:

Alternate angles are equal in measure, therefore:

$\angle E=105^{\circ}$

Then, The angles E, JEA and 32° add up to 180° because they form a straight angle. So:

$\begin{gathered} 105+\angle JEA+32=180 \\ 137+\angle JEA=180 \\ 137+\angle JEA-137=180-137 \\ \angle JEA=43 \end{gathered}$

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1 year ago

If s=7 cm and t= 24 cm, what is the length of r?

marin [14]

A^2 + B^2 = C^2.

so 49 + 576 = C^2

625 = C^2

Now find the square root of 625.

25 = C (in your case r)

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4 years ago

A company earns P dollars by selling x items, according to the equation P(x)=-0.002x^2+5.5x-1000. How many items does the compan

san4es73 [151]

So.. check the picture below

that's when the profit gets maximized

$\bf \qquad \textit{vertex of a parabola}\\ \quad \\

\begin{array}{lccclll}
P(x)=&-0.002x^2&+5.5x&-1000\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
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3 years ago

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m. Based on past experience the company has determin

Gala2k [10]

Answer:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.

We can consider 8 am = 0, and 8:30 am = 30, so $a = 0, b = 30$

Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Between 15 and 25, so:

$P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333$

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

8 0

3 years ago

Fill out First row is standard form <br><br> Second row is Factored Form already done for you.

DerKrebs [107]

Answer:

(x + 6)(x - 2) = x² + 4x - 12

(x + 2)(x - 8) = x² - 6x - 16

(x + 6)(x - 6) = x² - 36

(x - 5)(x - 1) = x² - 6x + 5

(x - 4)(x - 10) = x² - 14x + 40

(x + 2)(x + 5) = x² + 7x + 10

Step-by-step explanation:

Use FOIL.

(x + 6)(x - 2) =

F - first: x × x = x²

O - outer: -2 × x = -2x

I - inner: 6 × x = 6x

L - last: 6 × -2 = -12

(x + 6)(x - 2) = x² - 2x + 6x - 12

Now, combine like terms.

(x + 6)(x - 2) = x² + 4x - 12

(x + 2)(x - 8) = x² - 6x - 16

(x + 6)(x - 6) = x² - 36

(x - 5)(x - 1) = x² - 6x + 5

(x - 4)(x - 10) = x² - 14x + 40

(x + 2)(x + 5) = x² + 7x + 10

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2 years ago