Let w = cos(x)
The given equation turns into -5w^2 + 4w + 1 = 0. Use the quadratic formula to find that the two solutions, in terms of w, are:
The solution w = 1 leads to cos(x) = 1 which then becomes x = 0, x = 2pi, x = 4pi, etc. The general way to write this is x = 2pi*n where n is any integer. These angles are in radian mode.
The solution w = -0.2 leads to cos(x) = -0.2 which becomes x = arccos(-0.2) = 1.77215 approximately assuming your teacher wants the angle in radian mode. Unfortunately, I don't know the exact value of x here. There may not be an exact value, or finding this exact value may be well beyond the scope of this course.
£100 - £76.27
£23.73 amount in change would be given back
Answer:
Either (3,b) or (3,e) must be removed to form the above relation to be function.
Step-by-step explanation:
Given the relation between the elements of domain and range. we have to remove the link between two elements so that relation becomes a function.
A function is a relation in which each element in domain set maps into only one element of range set i.e one element can never have two images in range set.
Here, the element 3 in domain set maps into two element b and e in range set. Therefore, to form a function one link must be removed either
f(3)=b or f(3)=e
Hence, either (3,b) or (3,e) must be removed to form the above relation to be function.
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