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3 years ago

The diagonal of a TV set is 39 inches long. It's length is 21 more than the height. Find the dimensions of the tv

Mathematics

1 answer:

Anika [276]3 years ago

3 0

The height is 15 and the length is 36

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Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

2 years ago

Answer four of these question and you will be the brainliest. Answer this with solution please

lawyer [7]

(1) -1.79, 2 1/4, 2.54 , -4

negative -> positive

reorder: -4. -1.79, 2 1/4 (or 2.25), 2.54

(2) -x

The larger x is the smaller the value

-$40.75<-$25.20

BUT the larger after the minus the more you owe so Renae owes more.

(3)

sorry idk

(4)

78F-x=70F

|x|=8*F

4 0

3 years ago

Determine if there is a proportional relationship between the two quantities

Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Verify each table

Table a

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

$k=\frac{B}{A}$

For A=35, B=92 ---> $k=\frac{92}{35}=2.63$

For A=23, B=80 ---> $k=\frac{80}{23}=3.48$

the values of k are different

therefore

There is no proportional relationship between the two quantities

Table b

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

$k=\frac{D}{C}$

For C=20, D=8 ---> $k=\frac{8}{20}=0.40$

For C=12.5, D=5 ---> $k=\frac{5}{12.5}=0.40$

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

$D=0.40C$

7 0

3 years ago

1. 36(a+b)^2 - 49(a-b(^2

Brums [2.3K]

Answer:

-13a^2 + 170ab - 13b^2.

Step-by-step explanation:

1. 36(a+b)^2 - 49(a-b)^2

This is the difference of 2 squares: a^2 - b^2 = (a + b)(a - b).

36(a+b)^2 - 49(a-b)^2

= (6(a + b) + 7(a - b))( 6(a + b) - 7(a - b))

= (6a + 7a + 6b - 7b)( 6a - 7a + 6b + 7b)

= (13a - b)(-a + 13b)

If you require the expansion of this it is:

-13a^2 + 170ab - 13b^2.

8 0

3 years ago

What are the measures of ∠1 and ∠2?

Alinara [238K]

You have to show the picture

5 0

3 years ago