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vitfil [10]
3 years ago
12

It says I have 13 free answers left and then it says I used them all so I only get 2 free. why?

Mathematics
2 answers:
Klio2033 [76]3 years ago
6 0

Answer:

you have to use ads wich is stupid

Step-by-step explanation:

creativ13 [48]3 years ago
4 0

Answer: That used to happen to me but if you answer peoples questions it doesnt do that anymore because you are helping out

Step-by-step explanation:

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The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de
blsea [12.9K]

Answer:

1. 15.87%

2.  6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

  • Almost all the data lies within three standard deviation from the mean for a normally distributed data.
  • About 68% of data lies within one standard deviation from the mean.
  • About 95% of data lies within two standard deviations of the mean.
  • About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 6) =0.0228 = 2.28\%

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0
3 years ago
Can anyone help me on question 5?
svet-max [94.6K]
A) from 2 to infinity
B) from -infinity to -3
C) -3 to 2
D) -infinity to -3 and 2 to infinity
E) -infinity to infinity
F) no because the slope is linnear in 2 stops but has a different slope in both spots meaning it can’t be a linnear function or an exponential funtion
7 0
3 years ago
directions: find the y intercept of the line of fit. use 2 points from the line to find the slope. write an equation! please hel
allochka39001 [22]

Answer: y intercept is 4 and the slope is 4/5

Step-by-step explanation:

5 0
3 years ago
The sum of two numbers is 167. The second number is 29 less than three times the first number. Fine the numbers. The two require
Anettt [7]

Answer:

49 and 118

Step-by-step explanation:

Let the two numbers be x and y

x+y = 167

y = 3x-29

Substitute into the first equation

x+ 3x-29 = 167

Combine like terms

4x - 29 = 167

add 29 to each side

4x = 167+29

4x = 196

Divide by 4

4x/4 = 196/4

x = 49

x+y = 167

49+y = 167

y = 167-49

y =118

4 0
3 years ago
Read 2 more answers
The spinner above shows four equal sized sections. Suppose you spin the spinner two times. What is the theroetical probability o
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Answer:

2/4

is that what your asking

7 0
3 years ago
Read 2 more answers
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