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3 years ago

It says I have 13 free answers left and then it says I used them all so I only get 2 free. why?

Mathematics

2 answers:

Klio2033 [76]3 years ago

6 0

Answer:

you have to use ads wich is stupid

Step-by-step explanation:

creativ13 [48]3 years ago

4 0

Answer: That used to happen to me but if you answer peoples questions it doesnt do that anymore because you are helping out

Step-by-step explanation:

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Cal is buying T-shirts and shorts. T-shirts cost $12 and shorts cost $25. He plans on spending no more than $160 and wants to bu

aksik [14]

Answer at least what, u you missed part of the question

Step-by-step explanation:

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3 years ago

Four friends played darts last weekend. The table below shows the number of times that each friend hit the bulls-eye and the tot

Ludmilka [50]

Answer:

Becky

Step-by-step explanation:

Look at it.... i mean 21:35 is the greatest in fraction, decimal and percentage.

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3 years ago

Read 2 more answers

The width of Sandy’s little finger is 0.8 centimeter. What is the width in millimeters? Please explain because i need to show wo

lora16 [44]

8 millimeters. There are 10 millimeters in a centimeter. 0.8*10=8.

Have a nice day! :)

4 0

4 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

4 0

3 years ago

243.875 to nearest tenth, hundredth, ten, and hundred

IgorC [24]

243.875 to the nearest tenth = 243.9
243.875 to the nearest hundredth = 243.88
243.875 to the nearest ten = 240
243.875 to the nearest hundred = 200
This number is going to be a little bit trickier. The basic law of rounding is that is the number is less than 5, it is going to stay the same. If the number is greater than or equal to 5 then it rounds up to the next number.

8 0

3 years ago