Given:
The polynomials are:
![3x^2y^2-2xy^5](https://tex.z-dn.net/?f=3x%5E2y%5E2-2xy%5E5)
![-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
To find:
The completely simplified sum of the polynomials.
Solution:
We have,
![3x^2y^2-2xy^5](https://tex.z-dn.net/?f=3x%5E2y%5E2-2xy%5E5)
![-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
The sum of given polynomials is:
![Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=Sum%3D3x%5E2y%5E2-2xy%5E5-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
![Sum=-2xy^5+3x^4y+3x^2y^2](https://tex.z-dn.net/?f=Sum%3D-2xy%5E5%2B3x%5E4y%2B3x%5E2y%5E2)
Therefore, the sum of the given polynomials is
. It is a polynomial with degree 6 and leading coefficient -2.
Answer:
16
Step-by-step explanation:
x+y=30 solve for x x=30-y
substitute x with 30-y and solve
11.25x+22.4y=515.9
11.25(30-y)+22.4y=515.9
337.5+11.15y=515.9
11.15y=178.4
y=16
since we're solving for just large candles it's 16
if need small cangle number 30-16=14
Answer:
first term = 2 ...(given)
second term = f (2) = f (2-1) * 5 = 1 * 5 = 5. .....[according to the formula f(n) = f (n -1) *5 ]
third term = f (3) = f ( 3 - 1 ) * 5 = 2 * 5 = 10
fourth term = f (4) = f (4 - 1) * 5 = 3 * 5.= 15
fivth term = f (5) = f ( 5 - 1) * 5 = 4* 5. =20
answer is C 1/4
see attached picture, it is not exact but with rounding it comes out correct.
Answer:
First one is d and second one is c
Step-by-step explanation:
(6x+7)(x-8)
(6x)(x) = 6x^2
(6x)(-8) = -48
(7)(x) = 7x
(7)(-8) = -56
Add all like terms together and you get choice d.
(w+3)(w-3)
(w)(w) = w^2
(w)(-3) = -3w
(3)(w) = 3w
(3)(-3) = -9
Add all like terms together and you get choice c