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Brums [2.3K]
3 years ago
12

The most efficient way to administer a drug to its intended target site is to administer it intravenously (directly to the blood

). If the drug is administered in any other way (for example orally, nasal inhalant, or skin patch), then some of the drug is typically lost due to absorption before it gets to the blood. By definition, the bio-availability of a drug (F) measures the effectiveness of a non-intravenous method compared to an intravenous method. The bio-availability of intravenous dosing is 100%, F = 1. Let the functions Ci and Co give the concentrations of a drug in the blood, for times , using intravenous and oral dosing, respectively. (These functions can be determined through clinical experiments.) Assuming the same about the drug is initially administered by both methods, the bioavailability for oral dose (F0) is defined to be :
Where UAC is used in the pharmacology literature to mean "Area Under the Curve"

Suppose the concentration of a certain drug in the blood in mg/L when given intravenously is:

Ci(t) = 100e-0.3t

whereis measured in hours.

Suppose that the concentration of the same drug when delivered orally is:

C0(t) = 90(e-0.3t - e-2.5t)

Find F, the bio-availability of the drug.
Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

 F = 0.792

Step-by-step explanation:

Given:

- The function C_o :

                               C_o (t) = 90*(e^-0.3t - e^-2.5t)

- The function C_i :

                               C_i (t) = 100*e^-0.3t

The function:

                               F = UAC_o / UAC_i = \frac{\int\limits^n_0 {C_o} \, dt }{\int\limits^n_0 {C_i} \, dt }

Find:

- The factor F.

Solution:

- Determine UAC_o from the function given:

                       UAC_o = integral ( 90*(e^-0.3t - e^-2.5t) ) dt

                       UAC_o = -300*e^(-0.3t) + 36*e^(-2.5t)

Evaluate integral from infinity to zero:

                      | UAC_o | = 300 - 36 = 264

- Determine UAC_i from the function given:

                       UAC_i = integral ( 100e-0.3t ) dt

                       UAC_i = -333.333*e^(-0.3t)

Evaluate integral from infinity to zero:

                      | UAC_i | =  0 + 333.333 = 333.3333

- Evaluate factor F:

                          F =  | UAC_o | / | UAC_i |

                          F = 264 / 333.3333

                         F = 0.792

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Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

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In the exam 45% students failed and 550 students were successful. The total number of students appeared in the exam.
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In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to
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Step-by-step explanation:

From the statement:

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A(t): the amount memorized.

The key issue is translate this statement as equation "rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized"

memorizing rate is \frac{dA(t)}{dt}.

the amount that is left to be memorized can be expressed as the total minus the amount memorized, that is M-A(t).

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Answer:

The probability is 0.6923

Step-by-step explanation:

Let's call R the event that the next day rains, S the event that the next day has sunny weather, R2 the event that the station 2 predicts rain and S1 the event that station 1 predict sunny weather.

The probability that the next day has sunny weather given that station 1 predicts sunny weather for the next day and station 2 predicts rain is calculated as:

P(S/S1∩R2) = P(S∩S1∩R2)/P(S1∩R2)

Where P(S1∩R2) = P(R∩S1∩R2) + P(S∩S1∩R2)

So, the probability P(R∩S1∩R2) that the next day rains, Station 1 predicts sunny weather and Station 2 predicts Rain is calculate as:

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At the same way, the probability P(S∩S1∩R2) that the next day has sunny weather, Station 1 predicts sunny weather and Station 2 predicts Rain is calculate as:

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Then, the probability P(S1∩R2) that station 1 predicts sunny weather for the next day, whereas station 2 predicts rain is:

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Finally, P(S/S1∩R2) is:

P(S/S1∩R2) = 0.09/0.13 = 0.6923

6 0
3 years ago
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