Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
the angle c is 90°, it is a right triangle. (you see from the picture).
the sum of the interior angles are 180° (in all triangles)
so
180 - 90 - 29 =
61° (angle A)
----------------------
90 + 61 + 29 = 180°
Step-by-step explanation:
An important property of equations is one that states that you can add the same quantity to both sides of an equation and still maintain an equivalent equation. ... If you think of an equation as being like a balance scale, the quantities on each side of the equation are equal, or balanced.
X + y = 250
y + 40 = x
x + y = 250
y = x - 40
x + y = 250
- x + y = - 40
2y = 210
y = 105
Laura spent 105 hours, and Michael spent 145 hours there
*Brainliest Please ♡´･ᴗ･`♡
Answer: 20x < 100
subtract 20 from both sides
20 - 20 = 0
100 - 20 = 80
x < 80
