Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
1. x=3
2. x=2
3. 0 i think
4. y=6
5. x=7/5
Bonus: k=6
Step-by-step explanation:
combine like terms
Answer: 1,278
Step-by-step explanation: 2(18x18)+2 1/2(18x14)
p.e.m.d.a.s. 18x18= 324 18x14= 252
2x324= 648 2.5x252=630
648+630 =1,278
Answer:C
Step-by-step explanation:
the line above AB signifies that its a line segment
there are points for A and B
52 5/8 because 49 + 3 = 52 and 2/8 + 3/8 = 5/8
