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lisabon 2012 [21]
3 years ago
12

16 teams In a football league, each team plays each other twice , how many games are there in the football league in total ?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

120 games.

Step-by-step explanation:

We have been given that there are 16 teams in a football league. Each team plays each other twice. We are asked to find total number of games are there in the football league.

We will use formula \frac{n(n-1)}{2} to solve our given problem.

Each team will play matches with one team less as it will not play match with itself.

We will divide all number of matches by 2 to avoid repetition.

\frac{16(16-1)}{2}=\frac{16(15)}{2}=8*15=120

Therefore, there are 120 games in the football league.

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Construct an equation that has n = 6 as its solution. Use n on both sides of the equation.
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Answer:

See Explanation

Step-by-step explanation:

Required

Determine any equation where n = 6

n = 6

Add n to both sides

n + n = 6 + n

<em></em>2n = 6 + n<em> ----- This is 1 equation</em>

n = 6

Multiply both sides by n

n * n = 6 * n

<em></em>n^2 = 6n<em> ----- This is another</em>

<em></em>

n = 6

Add 5n to both sides

n + 5n = 6 + 5n

<em></em>6n = 6 + 5n<em> ---- This is another</em>

Subtract 10 from both sides

6n - 10 = 6 - 10 + 5n

6n - 10 = -4 + 5n

<em></em>6n - 10 = 5n - 4<em> --- This is another</em>

<em>You can have as many equations as possible</em>

4 0
3 years ago
Maggie has a box of crayons. 35 are orange, 12 are blue, 25 are green, and 7 are red. If she selects a crayon at random, which c
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orange

Step-by-step explanation:

3 0
3 years ago
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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
Darya [45]

Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

8 0
3 years ago
Logan owed his brother $7.50. For his birthday, Logan received $20 from his grandpa. After paying his brother back, how much mon
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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Pls, look at the picture for the question.
finlep [7]
B. 9*10^16 (because in question give it)


B. 3*10^9 (because answer to first question is divided by seconds in one year (365*24*60*60).
7 0
2 years ago
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