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storchak [24]
3 years ago
6

Can someone help me please???

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0
Let's start out with the general rule for simplifying fractions:

-- To simplify a fraction, look for a number that goes into
the numerator and denominator (a common factor). 

-- If you find one bigger than ' 1 ', then divide the numerator
and the denominator by it. 

-- Then try it again. 

-- When you don't find any common factor except ' 1 ',
then the fraction is in simplest form.
_________________________________________

On your Practice 9-2 sheet:

#1).  5/10
' 5 ' can go into both the numerator and the denominator,
so divide them both by it.  Then you have  1/2 .

#4).  3/15
' 3 ' can go into both the numerator and the denominator,
so divide them both by it.  Then you have  1/5 .

#7).  2/18
' 2 ' can go into both the numerator and the denominator,
so divide them both by it.  Then you have  1/9 .

#8).  25/60
' 5 ' can go into both the numerator and the denominator,
so divide them both by it.  Then you have  5/12 .

#9).  12/72
' 2 ' can go into both the numerator and the denominator,
so divide them both by it.  Then you have  6/36 .

That's not the simplest form yet.  ' 2 ' can go into both the
numerator and the denominator again, so divide them both by it. 
Then you have  3/18 .

That's STILL not the simplest form.  ' 3 ' can still go into both the
numerator and the denominator, so divide them both by it. 
Then you have  1/6 .  That's the simplest form.

#11).  The fraction of the test that will be word problems is

         (the number of word problems)
divided by
         (the total number of questions on the test) .

The total number of problems on the test is (20 + 10 + 5) = 35 .

So the word problems will be  5/35  of the test.
Simplify that.

Do EVERYTHING on this sheet the same way.  This sheet is
nothing but 14 different problems in simplifying fractions.
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Step-by-step explanation:

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I tried different numbers

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

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<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
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  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

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Step-by-step explanation:

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