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storchak [24]
3 years ago
8

Which table represents viable solutions for y = 5x, where x is the number of tickets sold for the school play and y is the amoun

t of money collected for the tickets?
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 100, negative 25, 40, 600. The second column is labeled money collected (y) with entries negative 500, negative 125, 250, 3000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 20, 20, 100, 109. The second column is labeled money collected (y) with entries negative 100, 100, 500, 545.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400. The second column is labeled money collected (y) with entries 0, 50, 255, 2000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 5, 65, 80, 200. The second column is labeled money collected (y) with entries 25, 350, 400, 1000.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

I think the second table.

Step-by-step explanation:

Because it is the correct one.

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4 0
4 years ago
He roots of x2 − (<br> ) + 34 are 5 ± 3i.
GrogVix [38]
Use the quadratic formula, x=\frac{-b+ \sqrt{ b^{2}-4ac} }{2a}
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in this case, a=1, c=34, b is unknown
from the roots, we can tell that -b+\sqrt{b^{2}-4ac } =2(5+3i)=10+6i

Note: the original equation already give b as -b, so -(-b)=10, b=10
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