Area of the trapezoid:

Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:

We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
Answer:
Step-by-step explanation:
x-3 = 0
x = 3
x + 4 = 0
x = -4
x - 2 = 0
x = 2
x = 3, -4, 2
Answer:
Letter D) 
Step-by-step explanation:
you have to pay $100 for the enrollment fee and w goes with 75 because you have to pay $75 per week.
Hope this helps
If triangle ABC is equilateral,solve for X56x-308
A: From the graph, car B was traveling faster.
Because the line of car B is more steep than the line of car A.
B:
The lines cross at (2,80), this means that the two cars were traveling at the same distance (80 miles) at the same time (2 hours).
C:
Since the line passes through the points (0,0) and (2,80)
So the unit rate or slope is 40 mph.
The distance which car A traveled in the first four hours = 4x40= 160 mph