<span>2500 + .42 X ≥ 8800 </span>
<span /><span><span>X <span>≥</span></span> 15,000</span>
<span /><span>The red circle is closed because the inequality is greater than or equal to 15,000
</span>
Answer:
- 8x - 6
Step-by-step explanation:
2(- 4x - 3)
- 8x - 2 × - 3
- 8x - 6
Answer:
Following are the solution to the given question:
Step-by-step explanation:
The population std. dev of the dog weight=8
Calculating the payout w s.t:
therefore, we assume that the weight of the dog is a normal distribution with std. deviation that is 8.
Answer:
Equation of a circle:
radius = the sq. rt of (x - h)^2 + (y - k)^2
Plug in the values for the center of a circle and the radius:
15 = the sq. rt of (x + 9)^2 + (y + 4)^2
(x + 9)^2 + (y + 4)^2 = 225
The answer is A or the first one.
<u>ANSWER: </u>
A scooter travels 18 miles in the same time a bike covers 8 miles.The rates of both scooter and bike are 8 miles per hour and 18 miles per hour
<u>SOLUTION:
</u>
Given, a scooter travels 18 miles in the same time a bike covers 8 miles.
The rate of the scooter is two miles per hour than twice the rate of the bike
We need to find both rates of scooter and bike.
Let the speed of scooter be x and speed of bike be y.
And, time taken to travel be t.
Then,
for scooter:


--- (1)
For bike:


--- (2)
Now, equate both (1) and (2)

On cross-multiplication we get
18y = 8x
4x – 9y = 0 ---- (3)
We also know that, rate of the scooter is two miles per hour than twice the rate of the bike.
x = 2 + 2y ---- (4)
Now substitute (4) in (3)
4(2 + 2y) – 9y = 0
8 + 8y – 9y = 0
9y – 8y = 8
y = 8.
Again substitute y value in (4)
x = 2 + 2(8) = 2 + 16
x = 18.
Hence, the rates of both scooter and bike are 8 and 18 miles per hour