Answer:
4
Step-by-step explanation:
Let's call the width W and the length L.
We know the width is 3 less than the length, so:
W = L - 3
And we know the area is 28, so:
28 = WL
If we solve for L in the first equation:
L = W + 3
And substitute into the second equation:
28 = W (W + 3)
28 = W² + 3W
0 = W² + 3W - 28
0 = (W + 7) (W - 4)
W = -7, 4
Since W can't be negative, W = 4 units.
Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Answer:
C -1
Step-by-step explanation:
