For this case we have that the cost of candies is given by:

If we have to:
c: Represents the cost of candy
p: Represents the number of pounds of candy
So, we can raise the following equation:

Answer:
The equation is:
Option C
Answer:
![\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
If you have two matrices:
![A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%5C%5Cand%5C%5CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7De%26f%5C%5Cg%26h%5Cend%7Barray%7D%5Cright%5D)
The sum of the matrices is:
![A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%2Be%26b%2Bf%5C%5Cc%2Bg%26d%2Bh%5Cend%7Barray%7D%5Cright%5D)
In this case we have:
![A=\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]\\\\\\B=\left[\begin{array}{cc}1&5\\0&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The <u>sum</u> is:
![A+B=\left[\begin{array}{cc}2+1&0+5\\-2+0&3+1\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%2B1%260%2B5%5C%5C-2%2B0%263%2B1%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5CA%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
The answer is:
![\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
Answer:
3rd and 5th options
Step-by-step explanation:
For f(x) = 3(16)^(3x/4):
There is no initial value, because exponents can be any real number (positive or negative), so #1 is false
Because exponents can be any real number (positive or negative), #2 is false
A positive number to the power of anything will always be positive, and not equal to 0, so #3 is true
The simplified value of this is 3((16)^(3/4) )^x = 3(2^3)^x = 3(8)^x, so #4 is false, but #5 is true.
The value of 9 (4x - 4) is 144
Step-by-step explanation:
9( 4x - 4)
x = 5
subsituting 5 in the place of x
= 9 (20 - 4)
=9 (16)
= 144
The value of 9 (4x - 4) is 144