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kiruha [24]
3 years ago
8

Jackson rides his bike from his home for 30 minutes at a fast pace. He stops to rest for 20 minutes, and then continues riding i

n the same direction at a slower pace for 30 more minutes. Sketch a graph of the relationship of Jackson’s distance from home over time.
Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

For the first 30 minutes, we will have a line with a given steepness, this will represent the 30 minutes riding at a fast pace.

Then he stops for 20 minutes, we will represent this with a constant line.

Then he again moves for another 30 minutes, but with a slower pace than in the first 30 minutes, then this line will be less steep than the first line.

A sketch of this situation can be seen below.

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<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>

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<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
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To find this you use the formula a = bh

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