Answer:
idk try someone else
Step-by-step explanation:
Y= <span><span><span>−25
--------- x
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THIS HELPS!</span></span></span>
A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
Answer:
First mechanic: 12.8 hours & Second mechanic:12.8 hours
First mechanic made 832$ & Second mechanic made 768$
Hope this is right. If not I apologize and please let me know:)
Step-by-step explanation:
First you would do 65+60=125. You do this to find how much they charge together. Then you would take the amount of money they make and divide that from 125: 1600/125=12.8. Now that you have 12.8 you would plug that in for each mechanic: 65 times 12.8=832 and 60 times 12.8=768. Now you have the amount of money each mechanic made and the amount of hours they worked.
/ also means division so the answer is 42.75
