Answer:
Yep. Those are 5 (-4)'s.
Step-by-step explanation:
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
72
Step-by-step explanation:
multiply by 16
Answer and Step-by-step explanation:
-6 and -10 are the answers.
This is because these numbers are less than -5, so they would work when plugged in for h in the inequality.
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