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3 years ago

CAN SOMEONE HELP ME PLEASE ASAP? I REALLY NEED HELP

Mathematics

1 answer:

Elan Coil [88]3 years ago

7 0

Answer:

Which one do u want help on because I can do the first 3 but not the rest

Step-by-step explanation:

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A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

3 0

3 years ago

Read 2 more answers

I need help with solving please! thank you!

agasfer [191]

Answer:

C (5,3)

Step-by-step explanation:

I hope it is correct because I don't know if it is hope you also have a good day and pass this test

7 0

3 years ago

Read 2 more answers

Write the first five terms of the geometric sequence, given a1= -16 and r= -1/4

RUDIKE [14]

Answer: -16, 4, -1, 1/4,?

Step-by-step explanation: the nth term of a GP is given by Un= ar^n-1

Where n= the term.

So substituting the values for each term will give you the answer above. I don't know if it's tiredness or what but my fifth term gives me the same value as my fourth term.

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A television station shows commercials for 1312 minutes each hour. How many 45-second commercials can it show? Enter your answer

Mama L [17]

I think the answer is 28

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3 years ago

QUESTION 19

Tju [1.3M]

Unsecured credit cards could possibly be the answer

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