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Answer:</u></h2>
Which ordered pairs are in the solution set of the system of linear inequalities?
y > Negative one-halfx
y < One-halfx + 1
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 0) and (4, negative 2). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 2, 0) and (2, 2). Everything below the line is shaded.
(5, –2), (3, 1), (–4, 2)
(5, –2), (3, –1), (4, –3)
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(5, –2), (3, 1), (4, 2)</u></h2>
(5, –2), (–3, 1), (4, 2)
Step-by-step explanation:
Answer:
The area of the sector is 9.43 ft^2
Step-by-step explanation:
Here, we want to find the area of the sector with a central angle of 30 degrees
To do this, we use the formula below;
Area of sector = theta/360 * pi * r^2
theta = central angle = 30 degrees
r = radius = 6 ft
Thus, we have it that;
Area of sector = 30/360 * pi * 6^2
= 30/10 * pi = 3 * 3.142 = 9.43 ft^2
Answer:
y = (2 x)/3 + 1/4
Step-by-step explanation:
Solve for y:
8 x - 12 y = -3
Subtract 8 x from both sides:
-12 y = -8 x - 3
Divide both sides by -12:
Answer: y = (2 x)/3 + 1/4
Hey! Your answer would be x = 6a/5
